• # question_answer A man's salary is increased by 10%. In order to have his salary back to the original amount, it must be reduced by x%, then value of x is A)  $11\frac{1}{9}%$                   B)  $1\frac{11}{9}%$            C)  $11\frac{9}{11}%$                 D)  $9\frac{1}{11}%$

(d): Similar to Q5 10% increase $\Rightarrow 1.1x$ Let decrease be p% $\Rightarrow 1.1x\text{ }becomes\,1.1x\frac{\left( 100-p \right)}{100}=x.$ $\Rightarrow 1.1\left( 100-p \right)=100$ $\Rightarrow 110-1.1p=100$ $\Rightarrow 1.1p=10$ $\Rightarrow p=\frac{10}{1.1}=\frac{100}{11}=9\frac{1}{11}%$