A) \[\left( \frac{-1}{18},\ \frac{-1}{3} \right)\]
B) \[\left( \frac{-1}{18},\ \frac{1}{3} \right)\]
C) \[\left( \frac{1}{18},\ \frac{-1}{3} \right)\]
D) \[\left( \frac{1}{18},\ \frac{1}{3} \right)\]
Correct Answer: D
Solution :
Let point of contact be (h, k), then tangent at this point is \[ky=x+h\]. \[x-ky+h=0\equiv 18x-6y+1=0\] or \[\frac{1}{18}=\frac{k}{6}=\frac{h}{1}\] or \[k=\frac{1}{3}\], \[h=\frac{1}{18}\].
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