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JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    The point of intersection of the latus rectum and axis of the parabola \[{{y}^{2}}+4x+2y-8=0\]

    A)            (5/4, ?1)                                    

    B)            (9/4, ?1)

    C)            (7/2, 5/2)                                  

    D)            None of these

    Correct Answer: A

    Solution :

               The required point is nothing but the focus of the parabola. Therefore \[{{(y+1)}^{2}}=-(4x-9)=-4\left( x-\frac{9}{4} \right)\]            \[S\equiv \left( -1+\frac{9}{4},\,-1 \right)\] or \[\left( \frac{5}{4},\,-1 \right)\].


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