A) \[{{y}^{2}}-8x=32\]
B) \[{{y}^{2}}+8x=32\]
C) \[{{x}^{2}}+8y=32\]
D) \[{{x}^{2}}-8y=32\]
Correct Answer: C
Solution :
Vertex \[(0,4)\]; focus \[(0,2)\]; \[\therefore \] \[a=2\] Hence parabola is \[{{(x-0)}^{2}}=-4.2(y-4)\] i.e.,\[{{x}^{2}}+8y=32\].
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