JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    The latus rectum of a parabola whose directrix is \[x+y-2=0\] and focus is (3, ? 4), is

    A)            \[-3\sqrt{2}\]                            

    B)            \[3\sqrt{2}\]

    C)            \[-3/\sqrt{2}\]                          

    D)            \[3/\sqrt{2}\]

    Correct Answer: B

    Solution :

               Distance between focus and directrix is \[=\left| \frac{3-4-2}{\sqrt{2}} \right|=\frac{\pm 3}{\sqrt{2}}\] Hence latus rectum \[=3\sqrt{2}\] (Since latus rectum is two times the distance between focus and directrix).


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