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JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    The equation of the parabola whose vertex is        (­?1, ?2), axis is vertical and which passes through the point (3, 6), is

    A)            \[{{x}^{2}}+2x-2y-3=0\]            

    B)            \[2{{x}^{2}}=3y\]

    C)            \[{{x}^{2}}-2x-y+3=0\]              

    D)            None of these

    Correct Answer: A

    Solution :

               \[{{(x+1)}^{2}}=4a(y+2)\]            Passes through (3, 6) Þ \[16=4a.8\] Þ \[a=\frac{1}{2}\]            Þ \[{{(x+1)}^{2}}=2(y+2)\] Þ \[{{x}^{2}}+2x-2y-3=0\].


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