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JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    Vertex of the parabola \[9{{x}^{2}}-6x+36y+9=0\] is

    A)            \[(1/3,\ -2/9)\]                         

    B)            \[(-1/3,\ -1/2)\]

    C)            \[(-1/3,\ 1/2)\]                         

    D)            \[(1/3,\ 1/2)\]

    Correct Answer: A

    Solution :

               The equation can be written as\[{{(3x-1)}^{2}}=-4(9y+2)\].            Hence the vertex is\[\left( \frac{1}{3},\,-\frac{2}{9} \right)\].


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