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JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    The equation of the latus rectum of the parabola \[{{x}^{2}}+4x+2y=0\] is             [Pb. CET 2004]

    A)            \[2y+3=0\]                                

    B)            \[3y=2\]

    C)            \[2y=3\]                                    

    D)            \[3y+2=0\]

    Correct Answer: C

    Solution :

               \[{{(x+2)}^{2}}=-2(y-2)\]            Equation of latus rectum is \[y-2=-\frac{1}{2}\] Þ \[y=\frac{3}{2}\].


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