A) \[y+\sqrt{3}(x-1)=0\]
B) \[y-\sqrt{3}(x-1)=0\]
C) \[y+\sqrt{3}(x+1)=0\]
D) \[y-\sqrt{3}(x+1)=0\]
Correct Answer: C
Solution :
\[m=\tan (120{}^\circ )=-\sqrt{3}\] = Slope of the line which passes through (?1, 0). Required equation, \[y-0=-\sqrt{3}(x+1)\] \[y+\sqrt{3}(x+1)=0\].You need to login to perform this action.
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