JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    The area of triangle formed inside the parabola \[{{y}^{2}}=4x\] and whose ordinates of vertices are 1, 2 and 4 will be [RPET 1990]

    A)            \[\frac{7}{2}\]                           

    B)            \[\frac{5}{2}\]

    C)            \[\frac{3}{2}\]                           

    D)            \[\frac{3}{4}\]

    Correct Answer: D

    Solution :

               Let co-ordinates of vertices \[=(a,\,1),\,\,(b,\,2),\,\,(c,\,4)\]                    \[a=\frac{1}{4},\]\[b=1,\,\,c=4\]. Area of triangle formed by                    \[\left( \frac{1}{4},\,1 \right)\,,\,\,(1,\,2),\,\,(4,\,4)\] is \[\frac{1}{2}\left| \begin{matrix}    1/4 & 1 & 1  \\    1 & 2 & 1  \\    4 & 4 & 1  \\ \end{matrix} \right|=\frac{3}{4}\].


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