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JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    The normal to the parabola \[{{y}^{2}}=8x\] at the point (2, 4) meets the parabola again at the point            [Orissa JEE 2003]

    A)            {?18, ?12}                                 

    B)            {?18, 12}

    C)            {18, 12}                                     

    D)            (18, ?12)

    Correct Answer: D

    Solution :

               We have \[{{t}_{2}}=-{{t}_{1}}-\frac{2}{{{t}_{1}}}\]            Since \[a=2,\,\,{{t}_{1}}=1\];  \[\therefore \] \[{{t}_{2}}=-3\]            \[\therefore \]The other end will be \[(at_{2}^{2},\,2a{{t}_{2}})\] i.e., (18, ? 12).


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