question_answer

The focal chord to \[{{y}^{2}}=16x\] is tangent to \[{{(x-6)}^{2}}+{{y}^{2}}=2\], then the possible value of the slope of this chord, are  [IIT Screening 2003]

A)            \[\{-1,\ 1\}\]                             

B)            {?2, 2}

C)            {-2, 1/2}                                    

D)            {2, ?1/2}

Correct Answer: A

Solution :

           From diagram, \[\theta ={{45}^{o}}\]                    Þ Slope = \[\pm 1\].