• # question_answer The ratio of a 2-digit number to the sum of digits of that number is$4:1$. If the digit in the unit place is 3 more than the digit in the tens place, what is the number? A)  63                   B)  36       C)  24                   D)         40

Let the digit at unit place be x and the digit at tens place be y, then the number $=10y+x$ Now, according to the question, $\frac{10y+x}{y+x}=\frac{4}{1}$ $\Rightarrow$            $10y+x=4y+4x$ $\Rightarrow$            $6y=3x$  $\Rightarrow$ $x=2y$        .....(1) Also,  $x=3+y$ $\Rightarrow$ $2y=3+y$     [From (1)] $\Rightarrow$  $y=3$and $x=6$  $\therefore$Number = 36