A) \[CO\] and \[C{{l}_{2}}\]
B) \[S{{O}_{2}}\] and \[C{{l}_{2}}\]
C) \[{{H}_{2}}S\] and \[B{{r}_{2}}\]
D) \[N{{H}_{3}}\] and \[S{{O}_{2}}\]
Correct Answer: B
Solution :
\[S{{O}_{2}}\] bleaches by reduction while chlorine bleaches colour of flowers by oxidation.
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