A) Reduced
B) Oxidised
C) Converted into a complex compound containing both \[Sn\] and \[Hg\]
D) Converted into a chloro complex of \[Hg\]
Correct Answer: A
Solution :
\[\overset{+2\,\,\,\,\,\,\,\,\,\,}{\mathop{SnC{{l}_{2}}}}\,+\overset{+1\,\,\,\,\,\,\,\,}{\mathop{2HgC{{l}_{2}}}}\,\to \overset{+4\,\,\,\,\,\,\,\,}{\mathop{SnC{{l}_{4}}}}\,+H{{g}_{2}}C{{l}_{2}}(s)\] In this reaction \[HgC{{l}_{2}}\] is reduced in \[Hg\].
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