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JEE Main & Advanced Chemistry Redox Reactions / रेडॉक्स अभिक्रियाएँ Question Bank Oxidation Reduction

  • question_answer
    \[{{H}_{2}}{{O}_{2}}\]reduces \[{{K}_{4}}Fe{{(CN)}_{6}}\]             [MP PMT 1985]

    A)                 In neutral solution          

    B)                 In acidic solution

    C)                 In non-polar solvent      

    D)                 In alkaline solution

    Correct Answer: B

    Solution :

           When \[{{H}_{2}}{{O}_{2}}\] reduces with \[{{K}_{4}}[Fe{{(CN)}_{6}}]\]. It is present in acidic solution.                    \[2{{K}_{4}}[Fe{{(CN)}_{6}}+{{H}_{2}}S{{O}_{4}}+{{H}_{2}}{{O}_{2}}\to \] \[2{{K}_{3}}[Fe{{(CN)}_{6}}]+{{K}_{2}}S{{O}_{4}}+2{{H}_{2}}O\]


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