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JEE Main & Advanced Chemistry Redox Reactions / रेडॉक्स अभिक्रियाएँ Question Bank Oxidation number and Oxidation state

  • question_answer
    The oxidation state of \[Cr\] in \[{{[Cr{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]}^{+}}\] is [AIEEE 2005]

    A)                 +3          

    B)                 +2

    C)                 +1          

    D)                 0

    Correct Answer: A

    Solution :

               \[{{\left[ Cr{{(N{{H}_{3}})}_{4}}C{{l}_{2}} \right]}^{+}}\]                    \[x+4\times (0)-2=1\]Þ \[x+0-2=1\]                                  Þ x = 1 + 2 = + 3.


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