A) + 2
B) + 3
C) + 4
D) + 5
Correct Answer: A
Solution :
\[_{26}Fe\xrightarrow{{}}[Ar]\,3{{d}^{6}}4{{S}^{2}}\] \[F{{e}^{++}}\xrightarrow{{}}\,[Ar]\,3{{d}^{6}}\,4{{S}^{0}}\] \[F{{e}^{+++}}\xrightarrow{{}}\,[Ar]\,3{{d}^{5}}4{{S}^{0}}\] In +2 state \[Fe\] is called Ferrous & in +3 state as ferric.You need to login to perform this action.
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