A) 195 Hz
B) 205 Hz
C) 190 Hz
D) 210 Hz
Correct Answer: B
Solution :
Initially number of beats per second = 5 \ Frequency of pipe = 200 ± 5 = 195 Hz or 205 Hz ...(i) Frequency of second harmonics of the pipe = 2n and number of beats in this case = 10 \ 2n = 420 ± 10 Þ 410 Hz or 430 Hz Þ n = 205 Hz or 215 Hz ... (ii) From equation (i) and (ii) it is clear that n = 205 HzYou need to login to perform this action.
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