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JEE Main & Advanced Physics Wave Mechanics Question Bank Organ Pipe (Vibration of Air Column)

  • question_answer
    An open pipe resonates with a tuning fork of frequency 500 Hz. it is observed that two successive nodes are formed at distances 16 and 46 cm from the open end. The speed of sound in air in the pipe is                                     [Orissa JEE 2003]

    A)            230 m/s                                  

    B)            300 m/s

    C)            320 m/s                                  

    D)            360 m/s

    Correct Answer: B

    Solution :

               Distance between two consecutive nodes                    \[=\frac{\lambda }{2}=46-16=30\]\[\Rightarrow \lambda =60\]cm = 0.6m                    \[\therefore \] \[v=n\lambda =500\times 0.6=300\]\[m/s\].


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