JEE Main & Advanced Physics Wave Mechanics Question Bank Organ Pipe (Vibration of Air Column)

  • question_answer
    Two closed organ pipes, when sounded simultaneously gave 4 beats per sec. If longer pipe has a length of 1m. Then length of shorter pipe will be, (v = 300 m/s) [Pb. PMT 2002]

    A)            185.5 cm                                

    B)            94.9 cm

    C)            90 cm                                      

    D)            80 cm

    Correct Answer: B

    Solution :

               For first pipe \[{{n}_{1}}=\frac{v}{4{{l}_{1}}}\]and for second pipe \[{{n}_{2}}=\frac{v}{4{{l}_{2}}}\]                    So, number of beats = \[{{n}_{2}}-{{n}_{1}}=4\]                    \[\Rightarrow \]\[4=\frac{v}{4}\left( \frac{1}{{{l}_{2}}}-\frac{1}{{{l}_{1}}} \right)\]\[\Rightarrow \]\[16=300\left( \frac{1}{{{l}_{2}}}-\frac{1}{1} \right)\]\[\Rightarrow \]\[{{l}_{2}}=94.9\]\[cm\]


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