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JEE Main & Advanced Mathematics Differential Equations Question Bank Order and degree of differential equations

  • question_answer
    The degree of the differential equation \[{{\left( 1+{{\left( \frac{dy}{dx} \right)}^{2}} \right)}^{3/4}}={{\left( \frac{{{d}^{2}}y}{d{{x}^{2}}} \right)}^{1/3}}\] is [Karnataka CET 2004]

    A)                 \[\frac{1}{3}\]        

    B)                 4

    C)                 9             

    D)                 \[\frac{3}{4}\]

    Correct Answer: B

    Solution :

                       \[{{\left[ 1+{{\left( \frac{dy}{dx} \right)}^{2}} \right]}^{3/4}}={{\left( \frac{{{d}^{2}}y}{d{{x}^{2}}} \right)}^{1/3}}\]Þ \[{{\left[ 1+{{\left( \frac{dy}{dx} \right)}^{2}} \right]}^{9}}={{\left( \frac{{{d}^{2}}y}{d{{x}^{2}}} \right)}^{4}}\]                                 Clearly, degree is 4.


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