A) \[P(A)=P(\bar{A})\]
B) \[P\,(A\cap B)=P(A'\cap B')\]
C) \[P\,(A)=P\,(B)\]
D) None of these
Correct Answer: C
Solution :
\[P(A)=P(B)\] As this gives \[P(A\cup B)=P(A)+P(B)-P(A\cap B)\] or \[P(A)=2P(A)-P(A)\]\[\Rightarrow P(A\cup B)=P(A\cap B).\]You need to login to perform this action.
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