JEE Main & Advanced
Chemistry
Solutions / विलयन
Question Bank
Numerical Value Type Questions - Solution & Colligative Property
question_answer
The freezing point of an 0.08 (m) \[NaHS{{O}_{4}}\] is\[-0.345{}^\circ C\]. Calculate the percentage of \[HSO_{4}^{-}ions\] that transfer a proton to water to form\[SO_{4}^{2-}ion\]. \[{{K}_{f}}\left( {{H}_{2}}O \right)=1.86mo{{l}^{-1}}kg\]