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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Numerical Value Type Questions - Solution & Colligative Property

  • question_answer
    The freezing point of an 0.08 (m) \[NaHS{{O}_{4}}\] is\[-0.345{}^\circ C\]. Calculate the percentage of \[HSO_{4}^{-}ions\] that transfer a proton to water to form\[SO_{4}^{2-}ion\]. \[{{K}_{f}}\left( {{H}_{2}}O \right)=1.86mo{{l}^{-1}}kg\]

    Answer:

    31.85


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