question_answer

A thin ring of 10 cm radius carries a uniformly distributed charge. The ring rotates at a constant angular speed of \[40\pi \,\,red\,\,{{s}^{-1}}\] about its axis, perpendicular to its plane. If the magnetic field at its centre is \[3.8\times {{10}^{-9}}T,\] then the charge (in coulomb) carried by the ring is close to \[({{\mu }_{0}}=4\pi \times {{10}^{-7}}\,N/{{A}^{2}})\].

Answer:

\[\left( 3\times 10{{\text{ }}^{-5}} \right)\]