question_answer

Water from a tap emerges vertically downwards with an initial speed of \[1.0\text{ }m{{s}^{-1}}\]. The cross-sectional area of the tap is \[{{10}^{-4}}{{m}^{2}}\]. Assume that the pressure is constant throughout the stream of water and that the flow is streamlined. The cross-sectional area (in \[{{m}^{2}}\]) of the stream, 0.15 m below the tap would be: \[\left[ Take\text{ }g=10\text{ }m{{s}^{-2}} \right]\]

Answer:

\[\left( \mathbf{5}\times \mathbf{1}{{\mathbf{0}}^{-5}} \right)\]