JEE Main & Advanced Mathematics Inverse Trigonometric Functions Question Bank Numerical Value Type Questions - Inverse Trigonometric Function

  • question_answer
    If a and b are the roots of the equation \[{{x}^{2}}-4x+1=0\] \[(a>b)\]then the value of \[f(\alpha ,\beta )=\frac{{{\beta }^{3}}}{2}\cos e{{c}^{2}}\,\left( \frac{1}{2}{{\tan }^{-1}}\frac{\beta }{\alpha } \right)+\frac{{{\alpha }^{3}}}{2}{{\sec }^{2}}\left( \frac{1}{2}{{\tan }^{-1}}\frac{\alpha }{\beta } \right)\]is

    Answer:

    56


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