question_answer

Two circular rings A and B, each of radius\[a=30cm\]are placed coaxially with their axes horizontal in a uniform electric field \[E={{10}^{5}}N/C\]directed vertically upward as shown in figure. Distance between centres of these rings A and B is\[h=40cm\]. Ring A has a positive charge \[{{q}_{1}}=10\mu C\]while ring B has a negative charge of magnitude\[{{q}_{2}}=20\mu C\], A particle of mass\[m=100\text{ }g\]and carrying a positive charge \[q=10\mu C\]is released from rest at the centre of the ring A. Calculate its velocity when it has moved a distance of\[40cm\]. (Take \[g=10m{{s}^{-2}}\]) if it is v m/s. Find \[v/\sqrt{2}\].

Answer:

6.00