JEE Main & Advanced Physics EM Waves Question Bank Numerical Value Type Questions - Electromagnetic Waves

  • question_answer
    The magnetic field of a plane electromagnetic wave is given by: \[\overrightarrow{B}={{B}_{0}}\hat{i}[cos(kz-\omega t)]+{{B}_{1}}\hat{j}cos(kz+\omega t)\] Where \[{{B}_{0}}=3\times {{10}^{-5}}T\] and \[{{B}_{1}}=2\times {{10}^{-6}}T.\] The rms value of the force (in newton) experienced by a stationary charge \[Q={{10}^{-4}}C\] at \[Z=0\] is:

    Answer:

    0.64


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