question_answer

  EMF diagram for iron is given as: \[\underset{\left( Fe=+6 \right)}{\mathop{E{}^\circ \left( volts \right)Fe{{O}_{4}}^{2-}}}\,\xrightarrow{+2.20}\underset{\left( Fe=+3 \right)}{\mathop{F{{e}^{3+}}}}\,\] \[\xrightarrow{+0.77}\underset{\left( Fe=+2 \right)}{\mathop{F{{e}^{2+}}}}\,\xrightarrow{-0.445}\underset{\left( Fe=+0 \right)}{\mathop{F{{e}^{0}}}}\,\]   Determine the value of \[E_{FeO_{4}^{2-}/F{{e}^{2+}}}^{0}\].    

Answer:

1.84