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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Numerical Value Type Questions - Electrochemistry

  • question_answer
    The e.m.f. of the cell \[Zn|Z{{n}^{2+}}(0.01M)\,|\] \[\left| F{{e}^{2+}}(0.001M) \right|\] at 298 K is 0.2905 then the value of equilibrium constant for the cell reaction\[{{10}^{x}}\]. Find x.

    Answer:

    10.85


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