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For the following electrochemical cell at 298 K, \[Pt\left( s \right)\left| {{H}_{2}}\left( g,1bar \right) \right|\] \[\left. {{H}^{+}}\left( aq,1M \right) \right|\] \[\left| {{M}^{4+}}\left( aq \right),{{M}^{2+}}\left( aq \right) \right|Pt\left( s \right)\] \[{{E}_{cell}}=0.092V\] when  \[\frac{\left[ {{M}^{2+}}\left( aq \right) \right]}{\left[ {{M}^{4+}}\left( aq \right) \right]}={{10}^{x}}\], Given: \[E_{{{M}^{4+}}/{{M}^{2+}}}^{0}=0.151V;2.303\frac{RT}{F}=0.059V\] The value of x is

Answer:

2.00