question_answer

If the de Broglie wavelength of an electron is equal to \[~{{10}^{-3}}\] times the wavelength of a photon of frequency \[6\times {{10}^{14}}\] then the speed (in m/s) of electron is equal to: (Speed of light \[=3\times {{10}^{8}}m/s\]) Planck's constant \[=6.63\times {{10}^{-34}}J.s\] Mass of electron \[=9.1\times {{10}^{-31}}kg\])

Answer:

\[\left( 1.45\times {{10}^{6}} \right)\]