JEE Main & Advanced
Mathematics
Differential Equations
Question Bank
Numerical Value Type Questions - Differential Equation
question_answer
The solution of \[\frac{dy}{dx}+\frac{y}{\left( 1+{{x}^{2}} \right)}=\frac{{{e}^{{{\tan }^{-1}}}}}{1={{x}^{2}}}\] is \[{{e}^{k\,{{\tan }^{-1}}x}}+2c\] then find k.