question_answer

There are two groups of compounds A and B. Group A contains three compounds \[P{{x}_{4}},Q{{y}_{3}},R{{z}_{2}},\] Group B also contains three compounds\[S{{x}_{4}},\,T{{y}_{3}},\,U{{z}_{2}}\]. Hybridization of each central atom of group A compounds is same as that of iodine in \[IBrC{{l}^{-}}\]while in group B compounds it is same as that of iodine in \[IBrC{{l}^{+}}\] Substituents X, Y and Z exhibit covalence of one in ground state. Then find the value of x/y. Where, x and y are total number of lone pairs present at central atoms of compounds of group A and B respectively.

Answer:

2