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JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Numerical Value Type Questions - Calorimetry

  • question_answer
    The specific heat of a substance is given by \[C=a+bT,\]where \[a=1.12\text{ }kJk{{g}^{-1}}{{c}^{-1}}\] and \[b=0.016\text{ }kJ-kg\,\,{{c}^{-1}}{{k}^{-1}}\]. The amount of heat (in KJ) required to raise the temperature of 1.2 kg of the material form 280 K to 312 K is.

    Answer:

    225.00


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