question_answer

Find the number of reactants among the given options which does not undergo Michael addition?

(I) \[{{C}_{6}}{{H}_{5}}CH=CHCOC{{H}_{3}}+{{C}_{6}}{{H}_{5}}COC{{H}_{3}}\]

(II) \[{{C}_{6}}{{H}_{5}}CH=CHC{{H}_{2}}CO{{C}_{6}}{{H}_{5}}+C{{H}_{2}}{{(COO{{C}_{2}}{{H}_{5}})}_{2}}\]

(III)

(IV) \[C{{H}_{2}}=CHCOC{{H}_{3}}+C{{H}_{3}}COC{{H}_{3}}\]

Answer:

2