question_answer
Diborane is a potential rocket fuel which undergoes combustion according to the reaction. \[{{B}_{2}}{{H}_{6}}\,\left( g \right)\,\,+\,\,3{{O}_{2}}\,\left( g \right)\,\,\xrightarrow{{}}\,\,{{B}_{2}}{{O}_{3}}\,\left( s \right)\,\,+\,\,3{{H}_{2}}O\,\left( g \right)\] From the following data, calculate the enthalpy change for the combustion of diborane. \[2B\,\left( s \right)\,\,+\,\,\left( 3/2 \right){{O}_{2}}\,\,\left( g \right)\,\,\xrightarrow{{}}\,\,{{B}_{2}}{{O}_{3}}\,\,\left( s \right)\] \[\Delta H\,\,=\,\,-\,\,1273\,\,kJ\,\,mo{{l}^{-1}}\] \[{{H}_{2}}\,\,\left( g \right)\,\,+\,\,\left( 1/2 \right)\,{{O}_{2}}\,\,\left( g \right)\,\,\xrightarrow{{}}\,\,{{H}_{2}}O\,\,\left( l \right)\] \[\Delta H\,\,=\,\,-286\,\,kJ\,\,mo{{l}^{-1}}\] \[{{H}_{2}}O\,\left( l \right)\,\,\xrightarrow{{}}\,\,{{H}_{2}}O\,\left( g \right)\] \[\Delta H\,\,=\,\,44\,\,kJ\,\,mo{{l}^{-1}}\] \[2B\,\left( s \right)\,\,+\,\,3{{H}_{2}}\,\left( g \right)\,\,\xrightarrow{{}}\,\,{{B}_{2}}{{H}_{6}}\,\left( g \right)\] \[\Delta H\,\,=\,\,36\,\,kJ\,\,mo{{l}^{-1}}\]
