A) 72
B) 74
C) 41
D) 53
Correct Answer: B
Solution :
We have, \[x=1.2424.....\] \[\Rightarrow \]\[100x=124.2424.......\] ?(i) Subtracting (i) from (ii), we get ?(ii) \[100x-x=123\] \[\Rightarrow \]\[99x=123\Rightarrow x=\frac{123}{99}=\frac{41}{33}\] \[\therefore \]\[p=41,q=33\] and \[p+q=41+33=74\]You need to login to perform this action.
You will be redirected in
3 sec