question_answer

The smallest number which when divided by 20, 25, 35 and 40 and leaves a remainder of 14, 19, 29 and 34 respectively is

A)  1394                     

B)              1404

C)  1664                     

D)              1406

Correct Answer: A

Solution :

    \[\therefore \] L.C.M. \[=5\times 2\times 2\times 5\times 7\times 2=1400\] 20 ? 40 = 25 ? 19 = 35 = 29 = 40 ? 34 = 6 \[\therefore \] required number = LCM ? 6 = 1400 ? 6 = 394.