A) 8
B) 2
C) 16
D) 4
Correct Answer: A
Solution :
(a): \[A\times B\times C={{2}^{x}}\times {{\left( {{2}^{2}} \right)}^{y}}\times {{\left( {{2}^{3}} \right)}^{z}}\] \[={{2}^{x+2y+3z}}\] \[\therefore x+2y+3z=\frac{1}{9}+\frac{8}{9}+\frac{18}{9}\] \[=\frac{27}{9}=3\] \[\therefore A\times B\times C={{2}^{3}}=8.\]You need to login to perform this action.
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