A) \[\frac{43}{3}\,\,cm\]
B) \[\frac{33}{15}\,\,cm\]
C) Cannot be determined
D) \[\frac{15}{3}\,\,cm\]
E) None of these
Correct Answer: C
Solution :
Explanation Let the base of the triangle be x Then the height of the triangle \[=\,\,\frac{3}{5}\,\,x\] \[\operatorname{Area}\,\,=\,\,\frac{1}{2}\times \frac{3}{5}x\times x=\frac{3}{10}{{x}^{2}}\] Now new height \[=\,\,\frac{\cancel{4}}{\underset{25}{\mathop{\cancel{1}00}}\,}\times \frac{3}{5}x+\frac{3}{5}x\,\,\,\,\,=\frac{3}{5}x+\frac{3}{125}x\frac{75x+3x}{125}\,\,=\,\,\frac{78x}{125}\] \[\operatorname{Base}\,\,=\,\,x-\frac{2x}{100}=\frac{98x}{100}\] So we have, \[\frac{1}{2}\times \frac{78x}{125}\times \frac{98x}{100}=\frac{3}{10}{{x}^{2}}\] Thus, we cannot determine the value of ?x?.
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