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7th Class Mental Ability Numbers Question Bank Number System

  • question_answer
    Stephen has three boxes whose total weight is \[\frac{\mathbf{121}}{\mathbf{2}}\] pound. If the first box weight is \[\mathbf{3}\frac{\mathbf{1}}{\mathbf{2}}\] pound more than the second box and third   box weight \[\mathbf{5}\frac{\mathbf{1}}{\mathbf{3}}\] pound more than the first box, then the weight of second box is ________

    A) \[\frac{289}{18}\,\,Pound\]        

    B) \[\frac{18}{289}\,\,Pound\]

    C) \[\frac{279}{18}\,\,Pound\]        

    D)   \[\frac{18}{279}\,\,Pound\]

    E)             None of these

    Correct Answer: A

    Solution :

    Explanation Let the weight of second box be x pound. Then according to question \[\operatorname{Weight} of\,\,Ist\,\,box =\,\,\left( x+\frac{7}{2} \right) Pounds\] \[\operatorname{Weight} of\,\,IIIst\,\,box =\,\,\left( x+\frac{7}{2}+\frac{16}{3} \right) Pounds\] Then, \[\operatorname{x}+x+\frac{7}{2}+x+\frac{7}{2}+\frac{16}{3}=\frac{121}{2}\] \[\Rightarrow \,\,\,3x=\frac{121}{2}-\frac{16}{3}-7\] \[\Rightarrow \,\,\,3x=\frac{263-32-42}{6}\,\,\,\Rightarrow \,\,3x=\frac{289}{6}\,\,\,\Rightarrow \,\,x=\frac{289}{18}\]           


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