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JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Nucleus, Nuclear Reaction

  • question_answer
    If the binding energy per nucleon in \[L{{i}^{7}}\]and \[H{{e}^{4}}\] nuclei are respectively 5.60 MeV and 7.06 MeV, then energy of reaction \[L{{i}^{7}}+p\to 2{{\ }_{2}}H{{e}^{4}}\] is [CBSE PMT 1994; JIPMER 2000]

    A)            19.6 MeV                               

    B)            2.4 MeV

    C)            8.4 MeV                                 

    D)            17.3 MeV

    Correct Answer: D

    Solution :

                       B.E. of \[L{{i}^{7}}=39.20\ MeV\]and \[H{{e}^{4}}=28.24\ MeV\]                    Hence binding energy of \[2H{{e}^{4}}=56.48\ MeV\]                    Energy of reaction \[=56.48-39.20=17.28\ MeV\].


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