A) \[1.25\times {{10}^{7}}\]
B) \[2.25\times {{10}^{7}}\]
C) \[3.25\times {{10}^{7}}\]
D) \[0.25\times {{10}^{7}}\]
Correct Answer: A
Solution :
\[E=\Delta m{{c}^{2}}=0.5\times {{10}^{-3}}\times {{(3\times {{10}^{8}})}^{2}}=4.5\times {{10}^{13}}j\] \[\Rightarrow E=\frac{4.5\times {{10}^{13}}}{3.6\times {{10}^{6}}}=1.25\times {{10}^{7}}kWH.\]
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