A) \[7.625\times 10\,MeV\]
B) \[10.5\times {{10}^{29}}\,MeV\]
C) \[2.8\times {{10}^{-28}}\,MeV\]
D) \[5.625\times {{10}^{29}}\,MeV\]
Correct Answer: D
Solution :
\[E=\Delta m{{c}^{2}}=1\times {{(3\times {{10}^{8}})}^{2}}=9\times {{10}^{10}}J\] \[\Rightarrow E=\frac{9\times {{10}^{16}}}{1.6\times {{10}^{-19}}}=5.625\times {{10}^{35}}eV\]\[=5.625\times {{10}^{29}}MeV.\]
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