A) \[_{36}^{89}Kr\]
B) \[_{36}^{90}Kr\]
C) \[_{36}^{91}Kr\]
D) \[_{36}^{92}Kr\]
Correct Answer: A
Solution :
\[_{o}{{n}^{1}}{{+}_{92}}{{U}^{235}}{{\to }_{56}}B{{a}^{144}}{{+}_{36}}K{{r}^{89}}+3{{\ }_{o}}{{n}^{1}}\]
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