A) \[_{7}^{14}N\]
B) \[_{7}^{13}N\]
C) \[_{5}^{13}B\]
D) \[_{6}^{13}C\]
Correct Answer: B
Solution :
\[_{6}{{C}^{12}}{{+}_{o}}{{n}^{1}}{{\to }_{7}}{{N}^{13}}{{+}_{-1}}{{\beta }^{o}}\]
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