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JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Nucleus, Nuclear Reaction

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    The nuclear reaction \[^{2}H{{+}^{2}}H\to {{\,}^{4}}He\] (mass of deuteron = 2.0141 a.m.u. and mass of He = 4.0024 a.m.u.) is [Orissa JEE 2002]

    A)            Fusion reaction releasing 24 MeV energy

    B)            Fusion reaction absorbing 24 MeV energy

    C)            Fission reaction releasing 0.0258 MeV energy

    D)            Fission reaction absorbing 0.0258 MeV energy

    Correct Answer: A

    Solution :

                       Total mass of reactants                    \[=(2.0141)\times 2=4.0282\ amu\]                    Total mass of products \[=4.0024\ amu\]                    Mass defect \[=4.0282\ amu-4.0024\ amu\]                    \[=0.0258\ amu\]                    \[\therefore \]Energy released\[E=931\times 0.0258=24\ MeV\]


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